1800=x^2+5x

Solution for 1800=x^2+5x equation:

1800=x^2+5x

We move all terms to the left:

1800-(x^2+5x)=0

We get rid of parentheses

-x^2-5x+1800=0

We add all the numbers together, and all the variables

-1x^2-5x+1800=0

a = -1; b = -5; c = +1800;
Δ = b2-4ac
Δ = -52-4·(-1)·1800
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-85}{2*-1}=\frac{-80}{-2}
=+40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+85}{2*-1}=\frac{90}{-2}
=-45
$